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给定一个

给定一个

给定一个

给定一个

1

Within a given process instance, multiple instances of a task can be created . The required number of instances is known at design time.

给定一个流程实例，创建一个任务多实例，在设计的时候就知道实例的数目。

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And, what you would want to do with the function, really, is be able to tell quickly what's the value at a given point ?

给定一个函数，你想要的其实是能够快速地知道，它在给定点的值？

5

Pascal's Theorem : The points of intersection of the pairs of opposite sides of a hexagon inscribed in a conic are collinear .

帕司卡定理：给定一个圆上的六边形，则此六边形三对对边直线的交点在同一直线上。

7

Given a query sequence , the sub-sequences are looked up in the index to reduce the amount of time and se arching involved.

给定一个被查询序列，将根据索引来查询子序列，从而减少查询次数和时间。

11

This says that, given an integer , the algorithm for converting that integer into a MyDouble is provided by the op_Implicit operator .

这表示，给定一个整数，将此整数转换为 MyDouble 的算法是由 op_Implicit 运算符提供的。

12

The problem is that given a search for a word , you want to be able to extend that search to particular , closely-related words .

要解决的问题是，给定一个要搜索的词，我们希望能够将搜索扩展到某些关系密切的词。

13

For a cyclic code , it is difficult to find the set of it 's covering polynomials.

给定一个循环码，求取它的覆盖多项式集合目前尚无系统的方法。

14

That is, given an argument x, the natural logarithm returns the power to which e must be raised to give the value x .

也就是给定一个参数 x ，该自然对数返回 e 的几次幂等于给定的值 x 。

16

Given a text string to be tested , and list of matching strings, find out which matching string the text string starts with.

给定一个待检查的文本字符串，以及一批开头匹配字符串，看看待检查的文本字符串以哪个匹配字符串开头。

17

Given a regex and a datum , a regex engine yields whether the datum matches a pattern and , if a match was found, what matched.

给定一个正则表达式和数据，正则表达式引擎将得到数据是否匹配模式及匹配内容（如果找到匹配）等结果。

19

First , the OpenLayers. Protocol. SQL. Gears class must be instantiated and given a database and table name.

首先，OpenLayers.Protocol.SQL.Gears 类必须被实例化并被给定一个数据库和表名。

21

This method returns the next component in the tray, given a starting component .

给定一个起始组件时，该方法返回组件栏中的下一个组件。

22

Given a sequence coll and an integer n , concatenating the results of coll. Take(n) and coll. Skip(n) yields the same sequence as coll.

如果给定一个序列 coll 和一个整数 n ，则连接 coll.Take （n ）和 coll.Skip （n ）的结果会生成与 coll 相同的序列。

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It gives an aggregates score from hundreds of movie reviews and provides that number as a percentage .

它依据数百个电影评论为电影给定一个总分并提供了一个百分比。

30

He was honored for solving , in 1930, the problem of Plateau, which asks whether a minimal surface exists for a given boundary .

他因解决了普拉托极小曲面问题而获此殊誉，该问题是问当给定一个边界时，是否存在一个极小曲面。

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